I'm new to this forum and have a question.I'm not looking for the answer but I need help in getting started with this problem. I just dont know where to start. Any way Here is the question.
A Pb2+ ion selective electrode is employed to deterimine lead concentration downstream from a mine. A 50mL sample is collected and returns a signal of -0.3200V. A second sample is spiked with 5mL of 6x10^-2M leadperchlorate and a signal of -0.2800V is observed. What is the concentration of Pb2+ in the sample?
The first thing I did was multiply (0.005L)(6x10^-2M leadperchlorate) = 3x10^-4 mole leadperchlorate than I dont know what to do?? Can some one give me some pointers