OK, we will look at your example:
Na
+ +
-OH + H
+ + Cl
- Na
+ + H
2O + Cl
-Now, if we just swap Na
+ and
-OH with Na as you suggest:
Na + H
+ + Cl
- Na
+ + H
2 + Cl
-The products are different - the same salt is formed, but in the first case we form water and in the second hydrogen. You cannot just replace sodium salts with sodium metal and get the same reaction.
Again for this question:
Your particles are: Mg
2+, Mg, and N
3-Particle combinations in a 3:2 ratio are:
3Mg
2+ + 2Mg
Mg
56+ <- an ion that does not exist
3Mg
2+ + 2N
3- Mg
3N
2 <- a neutral known compound
3Mg + 2Mg
2+ Mg
54+ <- an ion that does not exist
3Mg + 2N
3- Mg
3N
26- <- an ion that does not exist
3N
3- + 2Mg
Mg
2N
39- <- an ion that does not exist
3N
3- + 2Mg
2+ Mg
2N
35- <- an ion that does not exist
The only sensible answer is the second one.