Question: You have a 0.500 g sample of a substance with the empirical formula XBr2. When it is reacted with excess silver nitrate, 1.0198 g of insoluble silver bromide is formed according to the reaction below. Which element corresponds to X?(M.M. AgBr = 187.80 g/mol) XBr2 (s) + 2 AgNO3 (aq) → 2 AgBr (s) + X(NO3)2 (aq)
My Proposed Solution:
(0.5 g)/ (x + 160) = (1.0198/187.8 ) * 2
x = 187.8(0.5)/ ( 2 * 1.0198 ) - 160
x <0 ?
how can that be possible
can some one assist me with this question?