[dorin1993]

Hi
i have a question about Kornblum DeLaMare elimination. i didn't find any mechanism of it on web, and on my book there is no mechanism, just one example...
from the example shown I realized that:
R-O-O-H + B (a base) --> R=O + BH + OH-
meaning that the base attacked the H of the C  (R-CH2-O-O-H) --> BH + R-CH=O + OH-

so:
1. is it correct? that what it is?

2. can anyone give me a link (or explanation) to the mechanism of Kornblum DeLaMare elimination?

3. i had to give the product of the reaction (Kornblum DeLaMare elimination) of the molecule that i attached picture of and a base.
so base on what i understood: R-O-O-H + B (a base) --> R=O + BH + OH-
i wrote that the product are: Cyclohexanone + BH + OH-
is it correct?
and if it is - is there a continued reaction?

thank you 

[discodermolide]

Here is a link to the mechanism.
http://en.wikipedia.org/wiki/Kornblum–DeLaMare_rearrangement

[dorin1993]

i saw it. but it's Kornblum–DeLaMare rearrangement - not elimination. are they the same?

[BetaAmyloid]

In that wiki article it says that "The reaction, formally a rearrangement, ranks under the elimination reactions as already observed by the original authors."