April 25, 2024, 03:14:41 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Hess's Law  (Read 1758 times)

0 Members and 1 Guest are viewing this topic.

Offline Starfoth

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Hess's Law
« on: October 21, 2012, 06:53:59 PM »
I am given the enthalpies of combustion C=-393.5, H2=-285.8, C2H5(OH(=-1366.7

I need to find the standard enthalpy change (deltaH) of the reaction;
2C+2H2+H20(l)->C2H5(OH)

I keep getting 293.9, but i'm not sure if this is correct.
Logged

Offline Schrödinger

  • Chemist
  • Sr. Member
  • *
  • Posts: 1162
  • Mole Snacks: +138/-98
  • Gender: Male
Re: Hess's Law
« Reply #1 on: October 22, 2012, 03:55:15 AM »
Please show us the individual chemical equations you used to calculate the heats and arrive at the final given reaction.
Logged
"Destiny is not a matter of chance; but a matter of choice. It is not a thing to be waited for; it is a thing to be achieved."
- William Jennings Bryan

Offline Aegis6

  • Regular Member
  • ***
  • Posts: 11
  • Mole Snacks: +0/-0
Re: Hess's Law
« Reply #2 on: October 24, 2012, 06:05:56 PM »
I am not sure how you reached your conclusion, due to your lack of work, but when I ran through the problem I got 7.7kJ/mol Rxn.
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links