Thanks Borek, Yggdrasil.

I'm trying to tell you what i've understood, now-

After fixing L or D , i think due to stability differences those purely L or D are selected. I've also thought about some example now-

If there are 100 spots[surface of crystals..] where a process occurs, such that 50 are D and 50 are L. We add equal amounts of D and L reactant at each spot. Lets assume that at D spots only D-type reactant can react , while for all L spots only L-type reactant can react.Now the process requires somany other things without which it will not lead to complition.The probability of getting all of these at the same time at the same spotis very less , so only very few of these 100 [ say only 1] spot happens to have them all. So even if there are Ds available to D spots and Ls available to L spots due to less probability of presence of all required factors is less the process will complete only at 1 spot which might be D or L. So, the probability of occurence of subprocess with L is 50 out of 100 i.e.1/2 and the same for D .The probability of complete process[life...] occuring with L or D can't be difined with only examining 100 spots, as complete process occurs only at 1 spot. So, if we examine large no. of completely occured processes we might find that the probability of complete process[life...] occuring with L or D is 1/2. Here it means if we examine many lives we can define the probability for random selection mode as 1/2 each L and D. i.e. 1/2 would have Ls and 1/2 would have Ds.

Till yet, when 2 choises are given & only one is randomly selected, i was more tending to say that probability of getting selected is 1/2 each. But these

probability laws are applicable for large statistical data and random mode of selection. Here, there is absense of large statistical data.

Now, why only 1 of L or D is fixed is still remains to be confirmed by me. So, please help.

Hope that was not so bad way of telling this...

yours always endoknowledgic,

hrushikesh