Of course there is a secondary carbon in isobutane.
However, I was wrong in my proposing the secondary radical intermediate. No such reaction takes place, I had it confused with the reaction chlorine radical with an alkene.
But of course, there is possibility to eliminate HCl from t-butyl chloride, and after addition borane
and oxidation the needed alcohol can be obtained.
The whole question was regarding the details on how such a reaction would bee formed inn the first place. All I can think of at this moment is to react diatomic chlorine, uv, and the suggested isobutane. Reaction with diatomic bromine would result in higher yield, however, chlorine, being nonselective would result in the statistical result, that is abstract one of the 9 hydrogen atoms.
Elimination of such a secondary halide does produce satisfactory yields, SN2 reactions, among others can take place.
Substitution of the halide would be the best, two step mechanism (as opposed to three). However, I'm not arriving at any ideas.