Hi there ,,

Peace be upon U

can it be a psuedo-order reaction for a one-step reaction

if this hypothetical reaction is a one-step reaction:

A + B = C

could the rate of this reaction has an over all order which is a psuedo-order reaction

for example:

rate = K' [A] [ B]

change in [ B] is relativily so small

then:

rate = K* [A]

where K* = K' [ B](initial)

then the over all order is 1

could it be like this ?

or the concentrations exponents have the same as their coeffecients in the equation for a one-step reaction ?

because all the time my book says:

experimentally , is the only way to know for sure what the exponents are.

but if this statement is true ... this means it is also experimentally is the only way to determine the exponents in a one-step reaction

but I know previously that if I have a hypothetical one-step reaction:

A + B = C

then the rate would be as simple as:

rate = K [A]^1 [ B]^1

rate = K [A] [ B]

what is the right thing ??

help please