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Topic: Determining identity of acid in an electrochemical cell  (Read 3550 times)

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Offline BatMiteDimension

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Determining identity of acid in an electrochemical cell
« on: November 23, 2012, 09:10:26 PM »
Question: Based on the following electrochemical cell configuration, a measured cell potential of +0.149 V, and the use of the following list of acids and their respective dissociation constants; determine the identity of the unknown acid (HA). Ionic strength effects can be ignored. Assume that the Ka of the acid is sufficiently low such that the concentrations of HA and NaA do not deviate significantly from the values provided below.

Pt, H2 (1.00 atm) | HA (25.0 mM), NaA (50.0 mM) || S.H.E.

AcidKa
Acetic acid1.75 x 10-5
Boric acid5.81 x 10-10
Chloroacetic acid1.36 x 10-3
Glycolic acid1.47 x 10-4
Iodic acid1.7 x 10-1

How would I begin (and continue) solving this question?

Thank you!

Offline Borek

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Re: Determining identity of acid in an electrochemical cell
« Reply #1 on: November 24, 2012, 06:05:10 AM »
Finding pH from the potential.
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Offline BatMiteDimension

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Re: Determining identity of acid in an electrochemical cell
« Reply #2 on: November 24, 2012, 07:57:19 PM »
So is this the right way to do it?:

E = 0.05916 x pH
0.149 = 0.05916 x pH
pH = 2.52

Ka = ([H+][A-])/[HA]
Ka = ([10-2.52][10-2.52])/[0.025 - 10-2.52]
Ka = 4.5 x 10-4

Based on my result, I would guess it's Glycolic acid since it's the closest to it, but even then, it's not really very close. I think I did something wrong, can you point me in the direction of what I need to fix, please?

Thank you

Offline Borek

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Re: Determining identity of acid in an electrochemical cell
« Reply #3 on: November 25, 2012, 04:09:54 AM »
Ka = ([10-2.52][10-2.52])/[0.025 - 10-2.52]

You are given concentrations of HA and A-.
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Offline BatMiteDimension

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Re: Determining identity of acid in an electrochemical cell
« Reply #4 on: November 25, 2012, 11:26:04 AM »
So:

Ka=([10-2.52][0.05])/[0.025] = 0.00604 = 6.04 x 10-3

Is that correct? The value of Ka is still not close to any given in the table.

Offline Borek

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Re: Determining identity of acid in an electrochemical cell
« Reply #5 on: November 25, 2012, 11:38:53 AM »
The value of Ka is still not close to any given in the table.

No idea why - I don't see anything wrong about the solution.
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Offline BatMiteDimension

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Re: Determining identity of acid in an electrochemical cell
« Reply #6 on: November 25, 2012, 11:46:47 AM »
Could it possibly be my method of calculating pH?

Quote
E = 0.05916 x pH
0.149 = 0.05916 x pH
pH = 2.52

Offline Borek

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Re: Determining identity of acid in an electrochemical cell
« Reply #7 on: November 25, 2012, 12:47:35 PM »
I don't see anything wrong about the solution.
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