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Topic: Sandbox?  (Read 93340 times)

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Offline Borek

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Re: Sandbox?
« Reply #45 on: March 04, 2013, 04:04:18 AM »
Did I miss any

SMILES at Daylight site
http://www.daylight.com/dayhtml/doc/theory/theory.smiles.html
SMILES at wikipedia
http://en.wikipedia.org/wiki/SMILES
ChemSketch
http://www.acdlabs.com/download/
LaTeX
http://en.wikibooks.org/wiki/LaTeX/Mathematics)

I believe it is a good starting collection, at least for the forum. There is much more to LaTeX, but most of it is of no use for us.
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Offline billnotgatez

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Re: Sandbox?
« Reply #46 on: March 21, 2014, 07:37:43 AM »
Just smiles testing some ketones

CC(C)=O

O=C(C)CC or CCC(=O)C

O=C(C)CCC
CC(C)C(=O)C
O=C(CC)CC

Just smiles testing some acids

O=CO

CC(O)=O

CCC(=O)O

O=C(O)CCC or CCCC(=O)O

CCCCC(O)=O





« Last Edit: March 21, 2014, 08:06:42 AM by billnotgatez »

Offline billnotgatez

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Re: Sandbox?
« Reply #47 on: April 26, 2014, 03:30:54 AM »
Just playing with tex

[tex] \frac {(2)}{(4)} = \frac {(1)}{(2)} [/tex]

[tex] \frac {(P_1 . V_1)}{(n_1 . T_1)} = \frac {(P_2 . V_2)}{(n_2 . T_2)} [/tex]

« Last Edit: April 26, 2014, 03:45:23 AM by billnotgatez »

Offline Xenonman

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Re: Sandbox?
« Reply #48 on: April 29, 2014, 10:37:18 PM »
Zn(s) + 2 HCl(ac) :rarrow: H2 (g) + ZnCl2 (ac)

Zn+2(ac) + Y-4(ac)  :rarrow: [ZnY]-2(ac)

nZn+2=nY-4= 0.0011 mol

Don't mind me. Just me failing at making divisions in tex.
Yes, I wrote states as subscripts. That's the way it's done around here.
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Offline Borek

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Re: Sandbox?
« Reply #49 on: April 30, 2014, 02:32:00 AM »
Yes, I wrote states as subscripts. That's the way it's done around here.

There is no such thing as "here" here.

IUPAC rules are clear and they are defined to be used by everyone.
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Offline curiouscat

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Re: Sandbox?
« Reply #50 on: April 30, 2014, 03:02:23 AM »
Yes, I wrote states as subscripts. That's the way it's done around here.

Around here is where?

Offline curiouscat

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Re: Sandbox?
« Reply #51 on: April 30, 2014, 03:03:32 AM »
IUPAC rules are clear and they are defined to be used by everyone.

Yes the rules are clear but how does one mandate everyone to use them? :)

Offline Borek

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Re: Sandbox?
« Reply #52 on: April 30, 2014, 04:59:25 AM »
IUPAC rules are clear and they are defined to be used by everyone.

Yes the rules are clear but how does one mandate everyone to use them? :)

Technically you don't, but it is a matter of being clear and unambiguous. What is VO2+? IUPAC rules tell you how to write it in an unambiguous way, why not stick to them?
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Offline curiouscat

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Re: Sandbox?
« Reply #53 on: April 30, 2014, 08:27:16 AM »
Technically you don't, but it is a matter of being clear and unambiguous. What is VO2+? IUPAC rules tell you how to write it in an unambiguous way, why not stick to them?

Agreed.

Offline billnotgatez

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Re: Sandbox?
« Reply #54 on: April 30, 2014, 08:40:58 AM »
(ac)
I did a quick GOOGLE and did not find this one
I have yet to peruse the IUPAC rules

Offline Borek

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Re: Sandbox?
« Reply #55 on: April 30, 2014, 09:15:06 AM »
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Offline Xenonman

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Re: Sandbox?
« Reply #56 on: April 30, 2014, 10:01:44 AM »
(ac) comes from "acuoso", aqueous in Spanish. I used it all over my Olympiad exams, without any penalization, because the entire exam was in Spanish.

Those zinc equations were for an assignment. In Spanish again.

I was taught to use (ac), as you can see. This is what every future Olympic will be taught, so I'll try to show this discrepancy, and an example of what happens when they use (ac) instead of (aq). I'll use (aq) as long as I don't forget when posting here, also.

Honeste vivere, alterum non laedere, suum cuique tribuere.

Offline billnotgatez

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Re: Sandbox?
« Reply #57 on: May 03, 2014, 10:26:10 PM »
Some more practice

Cobalt(II) oxide
WIKI
[Co]=O
SPIDER
[O-2].[Co+2]

Cobalt(III) oxide
SPIDER
O=[Co]O[Co]=O

Cobalt(II,III) oxide
WIKI
[Co]=O.O=[Co]O[Co]=O
SPIDER
[Co+2].[Co+2].[Co+2].[O-2].[O-2].[O-2].[O-2]

Cobalt(II) carbonate
SPIDER
C(=O)([O-])[O-].[Co+2]

Offline billnotgatez

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Re: Sandbox?
« Reply #58 on: May 04, 2014, 05:26:43 AM »
testing

Glycerol or Glycerin C3H8O3
WIKI
C(C(CO)O)O
SPIDER
C(C(CO)O)O

Offline Borek

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Re: Sandbox?
« Reply #59 on: May 04, 2014, 06:41:14 AM »
Strange. Why C(C(CO)O)O when OCC(O)CO is much simpler? Perhaps wiki has some computer generated code.

OCC(O)CO
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