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Topic: How much excess Ox- needed?  (Read 4347 times)

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kumquat

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How much excess Ox- needed?
« on: January 11, 2006, 03:51:49 PM »
The question I'm stucked on is:
If the concentration of Ox- is .350M, how much excess Ox- (in moles) would be added to 25.00mL of a 0.0150M solution of Al^+3?

This would be a mol:mol ratio, right?
I got my eq.: Al^3+  +  3Ox-  -->  Al(Ox)3.
I did: .0150M/0.0250L  and then 3mol Ox/1mol Al...then I'm stucked.
What confuses me is the 0.350M because I do know how to use this data. Is this extra info that I don't need? If it is extra, then I'm done at the mol:mol, right?

Oh, Ox- is 8-hydroxyquinolinate, not Oxalate. ( but that doesn't really matter, I don't think)

Thanks in advance for any help.

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