Hi there
if we have a sample of .1 grams
this sample contains Mg(OH)2
the Mg(OH)2 in the sample has been titrated by 10ml of .08M HCl
calculate the percentage of Mg(OH)2 in the sample
I suggest the answer would be like the following:
number of moles of HCl is
.08X10/1000 = .0008 mole
one mole of Mg(OH)2 is titrated by 2 moles of HCl
So at the end point , Mg(OH)2 will has half the number of moles of HCl , ie>>.0004 mole
mass = #moles * molar mass
= .0004 * 58 = .0232 grams
percentage = .0232/.1 *100% = 23.2%
is it all right like that ? because some people told me that my answer is totally wrong !!!
help