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Topic: Gases: 0.0840 dm3 of a gas is collected by water displacement at 22.0oC  (Read 5057 times)

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Me-Me

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There are two parts to these two problems.  1.  Name the laws.  2.  Solve the problems.  I must have the correct set-up and answers for credit.

Problems:

1.   0.0840 dm3 of a gas is collected by water displacement at 22.0oC  
      and 99.8 kPa.  What volume would the dry gas occupy at standard  
      pressure and 22.0oC?  (water vapor pressure at 22.oC = 2.6 kPa.

2.   A gas volume increases from 50.0 dm3 to 110 dm3 when heated    
     from 75oC (Pressure constant).  What is the final temperature of  
     the gas?

Thank you :)
« Last Edit: April 09, 2005, 07:43:28 PM by Mitch »

Offline Donaldson Tan

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Re:Gases
« Reply #1 on: June 19, 2004, 10:53:08 AM »
Please refer to the URL below first before any posting. thank you.
http://www.chemicalforums.com/index.php?board=4;action=display;threadid=59

Use PV = nRT to solve both your problems. Assume you are working with dry gas all the time.
« Last Edit: June 19, 2004, 10:54:33 AM by geodome »
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Offline AWK

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Re:Gases
« Reply #2 on: June 20, 2004, 06:36:52 AM »
Pressure of dry gas for problem 1 is 99.8-2.6 = 97.2 hPa
for naming the laws see:
http://www.sru.edu/depts/educatio/students/winter/gaslaw.htm
AWK

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