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Topic: help with ion exchange reaction  (Read 1681 times)

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Offline brycebb

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help with ion exchange reaction
« on: December 27, 2012, 11:30:41 PM »
Hey guys, I just had a quick question regarding the reaction of copper sulfate and sodium hydroxide.  Now I know that the balanced equation would be CuSO4+2NaOH---> Cu(OH)2+Na2SO4.  The question I had was usually copper sulfate is copper sulfate pentahydrade, so there is 5 mol of water within the structure of the salt.  When drawing the balanced equation, would you instead use CuSO4*5H20, and if so I could not balance the coefficients for the reaction.  Is this because there would be water within the copper hydroxide as well?

Offline Hunter2

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Re: help with ion exchange reaction
« Reply #1 on: December 28, 2012, 03:48:53 AM »
CuSO4*5H20 exist only as solid. In aquaeous solution you have Cu2+ and SO42-.
If you add NaOH the main reaction is : Cu2+ + 2 OH- => Cu(OH)2. Na+ and SO42- are spectator ions and dont participate on the reaction.

Offline brycebb

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Re: help with ion exchange reaction
« Reply #2 on: January 02, 2013, 08:23:46 PM »
Ahh ok. thank you, I was just checking.

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