Hey guys, I just had a quick question regarding the reaction of copper sulfate and sodium hydroxide. Now I know that the balanced equation would be CuSO4+2NaOH---> Cu(OH)2+Na2SO4. The question I had was usually copper sulfate is copper sulfate pentahydrade, so there is 5 mol of water within the structure of the salt. When drawing the balanced equation, would you instead use CuSO4*5H20, and if so I could not balance the coefficients for the reaction. Is this because there would be water within the copper hydroxide as well?