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Topic: clarifying on stereoisomers of 1-isopropyl-1-cyclopentene  (Read 5636 times)

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Offline rleung

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clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« on: January 15, 2006, 09:08:14 PM »
Hi,

I just want to make sure here that there are no stereoisomers for 1-isopropyl-1-cyclopentene, right?  My book's solutions manual makes it sound like there is since it draws mirror images of both, but there is no chiral center in that molecule, and since the ring has only 6 carbons, it can only exist as cis, right?  Thanks so much.

Offline mike

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Re:clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« Reply #1 on: January 15, 2006, 09:51:25 PM »
Are you sure you have the right structure? cyclopentene has 5 carbons not 6.
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Offline rleung

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Re:clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« Reply #2 on: January 15, 2006, 09:56:23 PM »
Yes, 5 carbons only.  

But even if it were 6 carbons, it still couldn't have stereoisomers, right?  I mean, unless you count the isopropyl group being in an axial vs. equatorial position, but those are just configurations vs. actual stereoisomers, right?  Thanks.

Ryan

Offline mike

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Re:clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« Reply #3 on: January 15, 2006, 09:59:35 PM »
Yes I would tend to agree with you, I don't see any stereoisomers. :)
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Offline Albert

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Re:clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« Reply #4 on: January 16, 2006, 11:32:50 AM »
In my opinion, there can be E-Z isomers (also known as trans-cis).
« Last Edit: January 16, 2006, 11:37:16 AM by Albert »

Offline rleung

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Re:clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« Reply #5 on: January 16, 2006, 11:54:11 AM »
Hmm, how can there be E-Z isomers since the ring is less than 8 carbons in length?

Ryan

Offline Albert

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Re:clarifying on stereoisomers of 1-isopropyl-1-cyclopentene
« Reply #6 on: January 16, 2006, 12:12:51 PM »
Well, of course the Z isomer is not stable, but, if asked, I'd answer 1-isopropyl-1-cyclopentene is an E isomer. I mean, we can think of E and Z isomers for 1-isopropyl-1-cyclopentene, even if we cannot yield the Z one.

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