to cross a river that is 1km wide, with a current of 6km/hr, a boat that is perpendicular to the far bank, the boat speed is 10km/hr. at what position will the boat actually contact the far bank? what direction should the boat have to cross directly across?

the first part i did this 10^{2}+6^{2}=11.6km/h is the diagonal speed

time=1/10= .1 distance = .1x 11.6 is the distance

and from here the acutal distance would be =squareroot1.16^{2}-1^{2} which comes to be 0.58km

and the second part would it be the inverse tan of of 1/10 = 5.7degrees but to get the total degrees would it jsut be 180+5.7= 185.7 degress

does this seem right?