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Topic: What is the molarity of the solution?  (Read 6156 times)

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Offline Sis290025

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What is the molarity of the solution?
« on: January 20, 2006, 12:52:30 PM »
A solution is prepared by dissolving 171 g of CdCl2 in enough water to make 250.0 mL of solution. If the density of the solution is 1.556 g/mL, what is the molarity of the solution?
 
 
a.0.440 M  
 
b.3.73 M  
 
c.0.933 M  
 
d.0.684 M  


Molarity = (mol solute)/(L solution)

Now my key question of this problem is about the given density. How do you use it (if you do use it)?

Normally, I would do so:

171 g CdCl2 * (1 mol CdCl2/183.311 g CdCl2) = 0.9328409 mol CdCl2

It is given that the solution volume = 250 mL = 0.250 L.

M = 0.9328409 mol CdCl2/0.250 L = 3.73 M

But the density is confusing me.

Please help soon.

Thank you.


Offline Alberto_Kravina

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Re:What is the molarity of the solution?
« Reply #1 on: January 20, 2006, 01:12:31 PM »
You don't need the density to calculate the molarity in this case!

c=n/V

n=m/M = 0.9328409 mol

V=0.25L

c=0.9328409 mol / 0.25L = 3.73 mol/L
« Last Edit: January 20, 2006, 01:15:12 PM by Alberto_Kravina »

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