[orgo814]

I am having trouble assigning oxidation #s to the elements in cyclo(HN-BH)3. I drew the ring correctly and know that the H on B is -1 and H on N is +1. But, just focusing on B (since if I figure that out I'm sure I'll figure out the rest). I know H is -1 on the B so that takes an electron leaving it +1. It is bonded to TWO Nitrogen atoms on each side. N is obviously more electronegative than B and needed 3 electrons to complete its octet, I assumed each nitrogen would take 3 leaving it +7. But, the answer is +3. Can someone please tell me what I'm doing wrong here and what's wrong with my reasoning?

[Hunter2]

Hydrogen is -1 in BH compounds and +1 in NH compounds. What means Borone has to be +3 and Nitrogen -3 .

Boron will give all the electrons 1 to hydrogen and 2 to Nitrogen. Nitrogen receives one electron from hydrogen and 2 from Boron.