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Topic: Thermo Question involving the Virial Equation  (Read 2194 times)

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Offline akaEMILY

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Thermo Question involving the Virial Equation
« on: January 26, 2013, 07:26:54 PM »
For Argon's isotherm at 300K:

p/MPA                0.4000, 0.5000, 0.6000, 0.8000, 1.0000
Vm/(dm3mol−1) 6.22808, 4.9736, 4.1423, 3.1031, 2.4795
p/MPA                1.5000, 2.000, 2.5000, 3.000, 4.000
Vm/(dm3mol−1) 1.6483, 1.2328, 0.98357, 0.81746, 0.60998

(a) Compute the second virial coefficient, B, at this temperature.


I know the virial equation is pVm = nRT (1 + A/Vm + B/Vm)

But I don't understand what the stats (data table) is representing? I'm so confused. Could someone show me how to start the problem?

Offline curiouscat

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Re: Thermo Question involving the Virial Equation
« Reply #1 on: January 27, 2013, 03:09:15 AM »

I know the virial equation is pVm = nRT (1 + A/Vm + B/Vm)

Typo?

Offline curiouscat

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Re: Thermo Question involving the Virial Equation
« Reply #2 on: January 27, 2013, 03:10:17 AM »
I'd just do a nonlinear numerical fit.

Offline akaEMILY

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Re: Thermo Question involving the Virial Equation
« Reply #3 on: January 27, 2013, 11:54:36 AM »
How do I do a nonlinar fit?

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