[hskid]

During the process of cooling, air surrounding the candle warms slightly.  Assuming all energy released by the drop of wax is absorbed by the air in a 2.5-L region surrounding the candle, what is the temp change of the air?  The density of air is 0.0012 g/mL, and its specific heat is .25cal/g°C.

What do i do?

edit: 23.3°C is final temp

[hskid]

do i use the mcΔT formula?  mass and temperature is not given?

[Borek]

mcΔT looks like a reasonable approach to me, the only problem is that the "drop of wax" is not defined in your question.

23.3°C is final temp

This is definitely incorrect - question asks about temperature CHANGE, not about the final temperature (which can't be calculated from the data given).

[Stovn0611]

q=mcΔT (for the air)
q=(0.0012*2.5)(0.25)(23.3-initial temperature)

Since you're trying to find the value of the initial temperature, I'm guessing that the problem would also give you the energy released by a drop of wax(it might give energy released in Joules so make sure to convert to calories if so)