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Topic: Molarity task  (Read 6792 times)

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Offline Maciejczyk

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Molarity task
« on: February 18, 2013, 04:49:28 PM »
Hello,

Please can someone explain this task extacly to me?

I would be grateful.

What mass of NaOH (Mr = 40) is required to make 0.5L of a 0.2M solution?

Offline sjb

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Re: Molarity task
« Reply #1 on: February 18, 2013, 05:14:54 PM »
Hello,

Please can someone explain this task exactly to me?

I would be grateful.

What mass of NaOH (Mr = 40) is required to make 0.5L of a 0.2M solution?

What are your thoughts? What, for instance does Mr=40 mean, or 0.5L, 0.2M? Please check the forum rules.

Offline Borek

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Re: Molarity task
« Reply #2 on: February 18, 2013, 05:40:31 PM »
Please read forum rules.

You have to show your attempts at solving the question to receive help. This is a forum policy.
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Offline Arkcon

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Re: Molarity task
« Reply #3 on: February 18, 2013, 06:03:00 PM »
This is a cute question -- I got almost this exact one during my first job interview.  I couldn't solve it.  :(  But I got the job anyway. ;)  That Mr for NaOH, what are the units for that value?  Try to find it, even if the problem doesn't specify the units.  It might help you understand this problem.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline Maciejczyk

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Re: Molarity task
« Reply #4 on: February 18, 2013, 06:55:34 PM »
Oh, I am sorry, my bad. Here is description:

to determine the number of moles (mol) present or the molar (M or mol/L, moldm-3) concentration, where m is the mass in grams, Mr is the relative molecular mass (the mass of 1 mol of a chemical) and V is the volume in litres (L or dm3). Don’t confuse m, M, Mr and mol they represent different things.

mol =  m/Mr
M = m/( Mr x V)
mol = M x V

Offline AWK

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Re: Molarity task
« Reply #5 on: February 18, 2013, 07:16:23 PM »
M = m/( Mr x V)
Hence calculate m.
AWK

Offline Maciejczyk

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Re: Molarity task
« Reply #6 on: February 19, 2013, 04:30:19 AM »
Thank you!


Is this good result?

M = m/( Mr x V)
M = 0.5/(40 x 0.2)
M = 0.5 / 8 = 0,0625

Offline sjb

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Re: Molarity task
« Reply #7 on: February 19, 2013, 04:44:24 AM »
Thank you!


Is this good result?

M = m/( Mr x V)
M = 0.5/(40 x 0.2)
M = 0.5 / 8 = 0,0625

What are your units?

Offline Maciejczyk

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Re: Molarity task
« Reply #8 on: February 19, 2013, 05:06:13 AM »
M = m/( Mr x V)

M = 0.5L / (40(?) x 0.2M)
M = 0.5L / 8(?) = 0,0625(?)


Any advises?


Offline Borek

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Re: Molarity task
« Reply #9 on: February 19, 2013, 05:19:22 AM »
Assuming Mr is a molar mass, what are units of molar mass?
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Offline Maciejczyk

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Re: Molarity task
« Reply #10 on: February 20, 2013, 04:48:05 AM »
Mr is the relative molecular mass (the mass of 1 mol of a chemical)

Offline Borek

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Re: Molarity task
« Reply #11 on: February 20, 2013, 05:47:58 AM »
Sigh, stop dodging the question.
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Offline Arkcon

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Re: Molarity task
« Reply #12 on: February 20, 2013, 07:16:54 AM »
Mr is the relative molecular mass (the mass of 1 mol of a chemical)

Awesome.  So, One mole of NaOH weighs 40 ... units?  And once you have that, and you know molarity is moles per liter, and you know the molarity you want, and the volume (given to you as some fraction of a liter), can you then solve it -- keeping the units in pace after each number so you can keep track of everything and we (and your instructor on an exam) can see where you're getting everything?
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline Maciejczyk

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Re: Molarity task
« Reply #13 on: February 24, 2013, 08:19:52 AM »
Please tell me if these are right calculations for this task.
http://s15.postimage.org/4dippo83f/calculation.jpg




Offline Arkcon

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Re: Molarity task
« Reply #14 on: February 24, 2013, 08:29:54 AM »
You get the correct answer.  Do you understand the meaning behind the labels on each box?  If you know it well, you'll be better off come examination time.  Or you know, when you actually have to prepare a solution in the laboratory.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

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