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Topic: Help with Organic Chemistry mechanism with NaOH?  (Read 12883 times)

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Offline phoenixrising

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Help with Organic Chemistry mechanism with NaOH?
« on: February 27, 2013, 07:18:47 PM »


I'm not sure how to solve this one :(

In my notes I have:

Deprotonation occurs at the alpha-C containing 2 hydrogens so that the reaction can go on to the alpha-beta unsaturated ketone via dehydration of the aldol addition product to form the aldol condensation product.

I don't what what's going on anymore

Offline discodermolide

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #1 on: February 27, 2013, 07:23:35 PM »
What is the compound at under the scheme?
O=C(/C=C/C1=CC=CC=C1)C(C)C
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Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #2 on: February 27, 2013, 07:35:16 PM »
What is the compound at under the scheme?
O=C(/C=C/C1=CC=CC=C1)C(C)C

What i guessed it would look like :(

Offline discodermolide

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #3 on: February 27, 2013, 07:45:32 PM »
Well you missed out a complete ring.
OK the CH2 protons next to the ketone, one is removed by NaOH to give what?
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Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #4 on: February 27, 2013, 07:51:25 PM »
Well you missed out a complete ring.
OK the CH2 protons next to the ketone, one is removed by NaOH to give what?

The C is deprotonated...
OH- attacks one of the 2 alpha hydrogens on the first cyclic structure, and in the process, 2 electrons go to that carbon 2, which now possesses a negative charge...So I'm assuming it will attack something?

Offline discodermolide

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #5 on: February 27, 2013, 07:54:55 PM »
You mean this structure
CC1CCC[CH-]C1=O.[Na+]?

Why is this "stable" and what will it attack?
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Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #6 on: February 27, 2013, 07:57:37 PM »
You mean this structure
CC1CCC[CH-]C1=O.[Na+]?

Why is this "stable" and what will it attack?

It's stable because of resonance...one of the bonds in the C=O bond can stabilize that negative charge and vice versa.

But that nucleophilic C will attack the aldehyde, right?
Particularly the carbonyl (C=O) on that aldehyde.

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #7 on: February 27, 2013, 08:02:00 PM »
Yes, both statements are OK. Now if it attacks the aldehyde carbonyl what product do you get?
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Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #8 on: February 27, 2013, 08:06:31 PM »
Yes, both statements are OK. Now if it attacks the aldehyde carbonyl what product do you get?

Ohhh :o
Ok ok! Can you hold on ooone second..imma draw you a full blown pushing mechanism because it's starting to make sense!!

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #9 on: February 27, 2013, 08:08:15 PM »
WOW, I'll wait.
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Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #10 on: February 27, 2013, 08:27:18 PM »
Yes, both statements are OK. Now if it attacks the aldehyde carbonyl what product do you get?

ok im back!!
This is what i did...



Is that right?

Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #11 on: February 27, 2013, 08:33:10 PM »
I'm not sure if that's my final/major organic product though  :(

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #12 on: February 27, 2013, 08:33:38 PM »
Yes, That's ok, one thing it would be worth showing the resonance structures of the anion.
However, there is still one more step to go, what is it?
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Offline phoenixrising

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #13 on: February 27, 2013, 08:42:00 PM »
Yes, That's ok, one thing it would be worth showing the resonance structures of the anion.
However, there is still one more step to go, what is it?

Alcohol condensation?

hold on lemme upload the next picture

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Re: Help with Organic Chemistry mechanism with NaOH?
« Reply #14 on: February 27, 2013, 08:47:00 PM »
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