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Topic: NH4Cl and Ca(OH)2: Potential reaction?  (Read 6811 times)

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Offline curiouscat

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NH4Cl and Ca(OH)2: Potential reaction?
« on: March 14, 2013, 09:54:58 AM »
NH4Cl has been reported in several patents to increase the solubility of Ca(OH)2 in water by an  order of magnitude.

Would there be any chance of a chemical reaction (Temp ~ 60 C)? I was hoping not, since dissolved Ca(OH)2 is the reagent of interest to me.

Possibilities I worried about:

(1) NH4Cl  :rarrow: NH3  :spinup: + HCl


(2a) NH4Cl + H2:rarrow: NH4OH + HCl

(1b & 2b) Ca(OH)2 + 2 HCl  :rarrow: CaCl2 + 2 H2O

(3) 2 NH4Cl + Ca(OH)2  :rarrow: 2 NH4OH + CaCl2
 

Are any of these reactions likely?

Previously I thought the solubility enhancing effects are from activity coefficents alone (at high ionic conc.) but the fact that NH4Cl is the only salt that has such a great effect on solubility of Ca(OH)2 causes  me to wonder.

Offline Borek

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Re: NH4Cl and Ca(OH)2: Potential reaction?
« Reply #1 on: March 14, 2013, 10:25:57 AM »
Technically adding NH4Cl you are not increasing solubility of Ca(OH)2, you are dissolving it in a weak acid.

Ca(OH)2 + 2NH4+ :rarrow: Ca2+ + 2NH3 + 2H2O
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Offline curiouscat

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Re: NH4Cl and Ca(OH)2: Potential reaction?
« Reply #2 on: March 15, 2013, 02:27:38 AM »
Technically adding NH4Cl you are not increasing solubility of Ca(OH)2, you are dissolving it in a weak acid.

Ca(OH)2 + 2NH4+ :rarrow: Ca2+ + 2NH3 + 2H2O

Thanks! No simple way of knowing if or not this affects the availability of the lime for a reaction, right?

e.g. Say I'd a reaction needing x parts of saturated lime solution before. If apparent solubility has been enhanced 10 times due to NH4Cl can I bank on (roughly) using 1/10th the quantity of lime solution?

Offline Borek

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Re: NH4Cl and Ca(OH)2: Potential reaction?
« Reply #3 on: March 15, 2013, 05:02:36 AM »
I would say it depends.

If what you need is just Ca2+ situation is quite different than if you need just high pH. And the situation is even more different if you need both.
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Offline curiouscat

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Re: NH4Cl and Ca(OH)2: Potential reaction?
« Reply #4 on: March 15, 2013, 05:58:02 AM »
I would say it depends.

If what you need is just Ca2+ situation is quite different than if you need just high pH. And the situation is even more different if you need both.

This reaction is what I need it for. I'd say I need the Ca2+ ions but not sure how I decide if I need the pH or not.

[*]C(Cl)C(O)[*]>>[*]C1OC1[*]

More specifically, this reaction:
c1ccccc1C(O)C[Cl]>>c1ccccc1C2OC2

Somehow the first trial (with NH4Cl as a solubility aid) gave a very low conversion  and I'm trying to debug why.....Equivalent amounts of Lime (with no NH4Cl added)  provided as a slurry gave almost quantitative conversion. Which was counter-intuitive to me. Dissolution ought to have helped but it actually hurt?
« Last Edit: March 15, 2013, 06:28:09 AM by curiouscat »

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Offline curiouscat

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Re: NH4Cl and Ca(OH)2: Potential reaction?
« Reply #6 on: March 15, 2013, 09:11:49 AM »
This is quite poor method and great result cannot be expected

http://link.springer.com/article/10.1007%2Fs00706-008-0083-5?LI=true#page-1
http://www.orgsyn.org/orgsyn/orgsyn/prepContent.asp?prep=cv1p0494
http://www.freepatentsonline.com/2582114.pdf

What's your basis for concluding that it is a poor method? None of those references have any Ca(OH)2 and definitely no  NH4Cl?  (That last patent does use Ca-Acetate! Interesting find! Thanks. Looking it up)

Note that this isn't for a small scale lab prep. So not using I2 / KOH / peroxy compounds has other cost / logistical / safety / effluent advantages. Ca(OH)2 seems a good choice; the search now is about ways to optimize the scheme.

What am I missing?

Sure those are alternatives. Maybe I wasn't clear: Ca(OH)2 by itself is proving not a bad alternative. I'd have expected Ca(OH)2 + NH4Cl to be better but somehow it is not. And that is the surprise.

The comparison  isn't between Ca(OH)2 and other routes but by Ca(OH)2 but with and without NH4Cl.

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