Calculate the amounts requested if 3.30 mol Fe2O3 + 2Al --> 2Fe +Al2O3
a - moles of Aluminum needed (Answer from the back - 45.6g Al)
b - moles of iron formed
c - moles of aluminum oxide formed (Answer from the back - 679g Fe2O3 )
I don't understand, this makes no sense!!!
3.30 moles of Fe2O3 is 527 grams
6.60 moles of Al is 178.2 grams
6.60 moles of Fe is 368.6 grams
3.30 moles of Al2O3 is 336.6 grams
you cant answer moles of aluminium oxide as grams!!!!!
is this really what the book says??