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### Topic: Simple Stoichiometry Question  (Read 13246 times)

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#### Navi00

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##### Re:Simple Stoichiometry Question
« Reply #15 on: January 30, 2006, 11:46:37 PM »
Hmmm... alright, I really appreshate the help =p

The book says mols of Al needed = 45.6g
« Last Edit: January 30, 2006, 11:47:06 PM by Navi00 »

#### mike

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##### Re:Simple Stoichiometry Question
« Reply #16 on: January 30, 2006, 11:48:13 PM »
So what exactly is the question from the book then?
There is no science without fancy, and no art without facts.

#### Navi00

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##### Re:Simple Stoichiometry Question
« Reply #17 on: January 30, 2006, 11:59:03 PM »
Alright here is the whole thing :

Calculate the amounts requested if 3.30 mol Fe2O3 + 2Al --> 2Fe +Al2O3

a - moles of Aluminum needed (Answer from the back - 45.6g Al)
b - moles of iron formed
c - moles of aluminum oxide formed (Answer from the back - 679g Fe2O3 )

#### mike

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##### Re:Simple Stoichiometry Question
« Reply #18 on: January 31, 2006, 12:17:02 AM »
Quote
Calculate the amounts requested if 3.30 mol Fe2O3 + 2Al --> 2Fe +Al2O3

a - moles of Aluminum needed (Answer from the back - 45.6g Al)
b - moles of iron formed
c - moles of aluminum oxide formed (Answer from the back - 679g Fe2O3 )

I don't understand, this makes no sense!!!

3.30 moles of Fe2O3 is 527 grams
6.60 moles of Al is 178.2 grams
6.60 moles of Fe is 368.6 grams
3.30 moles of Al2O3 is 336.6 grams

you cant answer moles of aluminium oxide as grams!!!!!

is this really what the book says??
There is no science without fancy, and no art without facts.

#### Navi00

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##### Re:Simple Stoichiometry Question
« Reply #19 on: January 31, 2006, 12:24:03 AM »
Word for word, hahaha...

#### mike

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##### Re:Simple Stoichiometry Question
« Reply #20 on: January 31, 2006, 12:29:10 AM »
Definetly something wrong there then, they are mixing up moles and mass (mol and grams).
There is no science without fancy, and no art without facts.

#### Navi00

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##### Re:Simple Stoichiometry Question
« Reply #21 on: January 31, 2006, 12:31:37 AM »
hehe, well thanks for the help again =p

EDIT : Also do you know of any good websites for more help with stoich?
« Last Edit: January 31, 2006, 12:42:44 AM by Navi00 »