April 27, 2024, 10:03:32 PM
Forum Rules: Read This Before Posting


Topic: Finding the Rate Constant  (Read 2367 times)

0 Members and 1 Guest are viewing this topic.

Offline Violet89

  • Regular Member
  • ***
  • Posts: 58
  • Mole Snacks: +1/-2
Finding the Rate Constant
« on: March 25, 2013, 10:10:20 PM »
A first order reaction has an activation energy of 68.1 kJ/mol and a frequency factor (Arrhenius constant) of 1.48 x 1012 sec -1. Calculate the rate constant at 18°C.

K = Ae^(- Ea / RT)

First off, I am confused as to how to enter K = Ae^(- Ea / RT) into my calculator. So, I do it a different way. A quick tutorial on how to do so would be much appreciated though!

My work:

(-68100 / (8.314 * 291.15)) ---> 2nd + LN ---> * (1.48 * 10^12) = 0.896

The correct given answer is 0.883. Why am I slightly off? I entered in those numbers exactly. Did I do something wrong, or does that difference not matter?

I would really appreciate any help or advice! :)

Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3652
  • Mole Snacks: +222/-42
  • Gender: Male
Re: Finding the Rate Constant
« Reply #1 on: March 26, 2013, 03:02:19 AM »
A first order reaction has an activation energy of 68.1 kJ/mol and a frequency factor (Arrhenius constant) of 1.48 x 1012 sec -1. Calculate the rate constant at 18°C.

K = Ae^(- Ea / RT)

First off, I am confused as to how to enter K = Ae^(- Ea / RT) into my calculator. So, I do it a different way. A quick tutorial on how to do so would be much appreciated though!

My work:

(-68100 / (8.314 * 291.15)) ---> 2nd + LN ---> * (1.48 * 10^12) = 0.896

The correct given answer is 0.883. Why am I slightly off? I entered in those numbers exactly. Did I do something wrong, or does that difference not matter?

I would really appreciate any help or advice! :)

What is the temperature?

Offline Violet89

  • Regular Member
  • ***
  • Posts: 58
  • Mole Snacks: +1/-2
Re: Finding the Rate Constant
« Reply #2 on: March 26, 2013, 09:52:32 AM »
A first order reaction has an activation energy of 68.1 kJ/mol and a frequency factor (Arrhenius constant) of 1.48 x 1012 sec -1. Calculate the rate constant at 18°C.

K = Ae^(- Ea / RT)

First off, I am confused as to how to enter K = Ae^(- Ea / RT) into my calculator. So, I do it a different way. A quick tutorial on how to do so would be much appreciated though!

My work:

(-68100 / (8.314 * 291.15)) ---> 2nd + LN ---> * (1.48 * 10^12) = 0.896

The correct given answer is 0.883. Why am I slightly off? I entered in those numbers exactly. Did I do something wrong, or does that difference not matter?

I would really appreciate any help or advice! :)

What is the temperature?

18°C ---> 291.15 K

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27665
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Finding the Rate Constant
« Reply #3 on: March 26, 2013, 10:07:55 AM »
I got 0.896 as well.

0.883 is what you get when you use 273 instead of 273.15 for °C -> K conversion.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Violet89

  • Regular Member
  • ***
  • Posts: 58
  • Mole Snacks: +1/-2
Re: Finding the Rate Constant
« Reply #4 on: March 26, 2013, 10:19:14 AM »
I got 0.896 as well.

0.883 is what you get when you use 273 instead of 273.15 for °C -> K conversion.

Thank you very much.

Sponsored Links