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Topic: Molecules of Cellulose  (Read 6682 times)

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danshodan

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Molecules of Cellulose
« on: February 04, 2006, 06:53:20 PM »
I have a wrapped box that weight 130.41 grams and i need to find the following:
Assuming your box and its wrapping are made only from cellulose C6H105, calculate the
number of molecules of cellulose contained in the box and wrapping material.
So i did the following:

130.41g C6H10O5 X 1 mol C6H10O5        6.02X10^23 mcs C6H10O5
                             ________________  X  __________________________ = 4.84 mcsC6H10O5
                            162.14g C6H10O5        1 mol C6H10O5
Am I correct? ???
« Last Edit: February 05, 2006, 12:25:00 AM by danshodan »

Offline Borek

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Re:Molecules of Cellulose
« Reply #1 on: February 04, 2006, 07:27:34 PM »
4.84 mcsC6H10O5

Am I correct? ???

Looks like you have lost 1023

But something is wrong with the question - cellulose is an organic polymer, not a single 6-carbon particle.
« Last Edit: February 04, 2006, 07:29:38 PM by Borek »
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danshodan

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Re:Molecules of Cellulose
« Reply #2 on: February 05, 2006, 12:28:19 AM »
Quote
Looks like you have lost 1023
What do you mean by that?


Quote
But something is wrong with the question - cellulose is an organic polymer, not a single 6-carbon particle.
Also, im not sure what u mean, are u refering to the given formula of cellulose?

Thanks for your help ;D

Offline Mitch

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Re:Molecules of Cellulose
« Reply #3 on: February 05, 2006, 01:20:22 AM »
He meant, you failed to multiply by 10^23 if you do the Math again you will see it does not match the answer you posted.
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danshodan

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Re:Molecules of Cellulose
« Reply #4 on: February 05, 2006, 12:13:20 PM »
Quote
He meant, you failed to multiply by 10^23 if you do the Math again you will see it does not match the answer you posted.

You are correct i forgot the 1023.
The answer should be 4.84X1023 mcsC6H10O5.
However I still am unsure about the other problem
Quote
But something is wrong with the question - cellulose is an organic polymer, not a single 6-carbon particle.
::)

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Re:Molecules of Cellulose
« Reply #5 on: February 05, 2006, 01:23:37 PM »
It means the problem is silly, because the chemical formula for cellulose isn't C6H105.
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danshodan

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Re:Molecules of Cellulose
« Reply #6 on: February 05, 2006, 04:58:01 PM »
Quote
It means the problem is silly, because the chemical formula for cellulose isn't C6H105.
Im not sure, since i didnt write the question, however I looked on wikipedia.com just now and it says
Quote
Cellulose (C6H10O5)n is a long-chain polymer polysaccharide carbohydrate, of beta-glucose. It forms the primary structural component of plants and is not digestible by humans.
But that doesn't really make a difference for me, because I can't change the question; I have to go by what I am told.
So.... assuming that the formula for cellulose is what is stated in the question, have i done things right and got the correct answer ???

kkrizka

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Re:Molecules of Cellulose
« Reply #7 on: February 05, 2006, 09:03:04 PM »
Im not sure, since i didnt write the question, however I looked on wikipedia.com just now and it says But that doesn't really make a difference for me, because I can't change the question; I have to go by what I am told.
So.... assuming that the formula for cellulose is what is stated in the question, have i done things right and got the correct answer ???

I think what that means is that cellulose if a long chain of n number of parts. Each part is C6H10O5. What I suppose the question is asking is how many of those parts the box has. If this is just an exercise question in your book, you shouldn't pay much attension to such details. And yes, you are correct.

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