February 27, 2021, 06:59:42 PM
Forum Rules: Read This Before Posting

Topic: balanced equation/ titration  (Read 4313 times)

0 Members and 1 Guest are viewing this topic.


  • Guest
balanced equation/ titration
« on: July 08, 2004, 11:14:11 AM »
If the question is : A 50.0 mL solution of H2C2O4 requires 24.35 mL of .125M NaOH to neutralize both protons. It takes 15.83mL of KMnO4 (product Mn2+) to react with all the oxalic acid in another 5.0 mL sample of oxalic acid (product CO2). A 2.500g sample containing iron(II)chloride is dissolved in acid and titrated with 31.87 mL of the KMnO4 solution.  How do you writie out the balanced equation for this reaction??? THere are three of them aren't there? And  how do you find the concentration of permanganate solution?

Offline Donaldson Tan

  • Editor, New Asia Republic
  • Retired Staff
  • Sr. Member
  • *
  • Posts: 3178
  • Mole Snacks: +261/-13
  • Gender: Male
    • New Asia Republic
Re:balanced equation/ titration
« Reply #1 on: July 08, 2004, 01:50:06 PM »
(1) H2C2O4 + 2NaOH => Na2C2O4 + H2O
This'll help you derrive the concentration of the ethandioc (oxalic) acid.

(2) 2[MnO4]- + 6H+ + 5H2C2O4 -> 10CO2 +2[Mn]2+ + 8H2O
This'll help u derrive the no. of moles of permangate in 15.83mL of solution.

(3) [MnO4]- + 5[Fe]2+ + 8H+ => [Mn]2+ + 5[Fe]3+ + 4H2O
This equation should help you confirm your answer derived from the results in (2)
"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

Sponsored Links