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Problem of the week - 20/05/2013
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Topic: Problem of the week - 20/05/2013 (Read 31990 times)
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Borek
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Problem of the week - 20/05/2013
«
on:
May 20, 2013, 02:03:14 PM »
When a sample of a rose red, rare mineral is reacted with 115.8 mL of 0.1 molar HCl, number of mLs of produced carbon dioxide (measured at 0°C and 1 atm) is identical to the molar mass of produced chloride. Identify the metal, name the mineral.
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ChemBuddy
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Schrödinger
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Re: Problem of the week - 20/05/2013
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Reply #1 on:
May 23, 2013, 06:18:23 AM »
Pbonyg ; Fcunrebpbonygvgr
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delta609
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Re: Problem of the week - 20/05/2013
«
Reply #2 on:
May 26, 2013, 01:44:02 PM »
I think it's Rhodocrosite (MnCO
3
), but the calculations don't add up.
MnCO
3
+ 2HCl
MnCl
2
+ CO
2
+ H
2
O
115.8 L of 0.1 molar HCl will produce .1289 mL CO
2
; whereas, the molar mass of MnCl
2
is 125.9 g/mol.
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Borek
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Re: Problem of the week - 20/05/2013
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Reply #3 on:
May 26, 2013, 02:24:29 PM »
Calculations don't add up, because it is not the correct answer. But you are not that far.
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ChemBuddy
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DrCMS
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Re: Problem of the week - 20/05/2013
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Reply #4 on:
May 26, 2013, 02:55:28 PM »
Sphaerocobaltite?
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Borek
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Re: Problem of the week - 20/05/2013
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Reply #5 on:
May 26, 2013, 03:58:33 PM »
Quote from: DrCMS on May 26, 2013, 02:55:28 PM
Sphaerocobaltite?
Yes. But Schrödinger was first
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ChemBuddy
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DrCMS
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Re: Problem of the week - 20/05/2013
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Reply #6 on:
May 27, 2013, 03:05:59 AM »
Quote from: Borek on May 26, 2013, 03:58:33 PM
Yes. But Schrödinger was first
Yes I see now with rot13
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Problem of the week - 20/05/2013