How much charge is required for the following reduction?
a) 1 Mole of MnO
4- to Mn
2+In the Solution, the follwing equation is mentioned
MnO
4- + 8H
+ + 5e
- Mn
2+ + 4H
2O
Here, 5 Moles of e
- are reqiured and the amount of charge required is 5F
I have the following questions.
1) How is the equation obtained ?
2) Is it possible to determine the no. of Moles of electron invovled in the reaction without knowing the equation.
Thank you for your Help.