Have you used density tables?

:O No!

It's a fairly simple question. If 100 g of the soln contains 60.16 g of H

_{2}SO

_{4} and 100 mL of the solution contains 90.24 g of H

_{2}SO

_{4}, all one needs to find out is how many mL of soln corresponds to 60.16 g H

_{2}SO

_{4}, because this volume of soln which corresponds to 60.16 g of H

_{2}SO

_{4}, also weighs 100 g (given).