[alina0031]

Which ions are in following dissolution: 0,1 M Na₂CO₃

I am really lost here.

My atempt:

Na₂CO₃ + 2 H₂O  H₂CO₃ + 2NaOH

(I am not that sure if this is correct, but I have tried to do something. I really hope you will help me)

Thank you!

[9-92-6-19]

First, seperate the primary ions as if water is not a reactant:

Na₂CO_3(s)  2Na⁺_(aq) + CO₃^2-_(aq)

Then find the ions that react with water (assuming you are not including aqua-complexes):

H₂O_(l) + CO₃^2-_(aq)  HCO₃^-_(aq) + OH^-_(aq)

Thus, there are Na⁺, CO₃^2-, HCO₃^-, and OH^- ions in solution with a much greater degree of HCO₃^- and OH^- ions than CO₃^2- ions; you can calculate this with the Kb value for CO₃^2-.

[alina0031]

First of all thank you for replying.

Does it mean that I have also have to let CO₃^2- react with water?


I am not English, so I didn't get the last part. But I know the that the K_b of CO₃^2- is 10^-3,68. What do I have to do with this K_b value? - And is the last part something I have to do or am I finish after I have let it react with water?