Yes. Pgas + δ g h
Ok. But this suggests that the pressure of the water does not depend on the temperature of the water (Pgas
will depend on the temperature of the gas, but still the pressure on the water doesn't depend directly on the temperature of the water
)? And that, if instead of having 25 cm3
of water I had 50 cm3
of ethanol (with the same gaseous pressure Pgas
over it), the pressure would be the same for both (if I'm at the same height from the surface, in the same gravitational field).
You're moving in circles and not reading enough / not solving enough numerical examples.
It's not very difficult to get numerical answers once you have the equations you need, in this case.
I can't find any questions asking me to find the pressure on a liquid in a static beaker. That suggests to me that it is very straightforward indeed, no need to look for numerical problems for such an obvious case. But things aren't clicking yet. When/if it looks like the equations are getting more complicated, I'll start looking for online papers or in a textbook, but until then it just feels like I'm missing something obvious.
Overdoing silly abstraction is killing you, if you ask me.
Since you're one of my most consistent teachers, the question for me to ask is: what should I be doing differently?