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Topic: mol%  (Read 4843 times)

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Offline gunnersaurus

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mol%
« on: June 25, 2013, 02:21:12 PM »
hi,

i have a fluid composition which states 28.61% mol of h2s.

i also have a product which is rated for use in up to 2 % h2s

how to i get the two values above into the same units to check compatibility of this product in the fluid? ???

Thanks

Offline billnotgatez

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Re: mol%
« Reply #1 on: June 27, 2013, 11:38:24 PM »
Do you mean H2S
Is the fluid H2O

Offline gunnersaurus

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Re: mol%
« Reply #2 on: June 28, 2013, 11:42:26 AM »
Yes i mean H2S

No the fluid is crude oil

Offline Borek

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Re: mol%
« Reply #3 on: June 28, 2013, 01:54:15 PM »
Crude oil with 28.61% H2S? Somehow this number doesn't look OK to me. I find it hard to believe H2S has that high solubility, unless the mixture is kept under some pretty high pressure.
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Offline gunnersaurus

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Re: mol%
« Reply #4 on: June 29, 2013, 10:20:24 AM »
6500 psi...

anyway, back to the conversion..?

Offline Borek

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Re: mol%
« Reply #5 on: June 29, 2013, 10:34:05 AM »
That's 440 atm, it no longer looks that impossible.

But I am not sure what the problem is - do you want to convert mole % to mass %?
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Offline gunnersaurus

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Re: mol%
« Reply #6 on: June 30, 2013, 09:09:27 AM »
yes i would like to convert it to % mass

Offline curiouscat

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Re: mol%
« Reply #7 on: June 30, 2013, 09:22:51 AM »
Technically depends on the exact composition of the crude. You could assume something like MW=120?

The rest is then arithmetic.  The assumption is iffy though.

Offline gunnersaurus

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Re: mol%
« Reply #8 on: July 01, 2013, 07:56:52 AM »
I have the composition but not the MW.

Can I simply multiply the % of each compound by the atomic mass of each compound, then add them together to get the overall MW for the fluid? :-\

Offline curiouscat

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Re: mol%
« Reply #9 on: July 01, 2013, 08:27:44 AM »
I have the composition but not the MW.

Can I simply multiply the % of each compound by the atomic mass of each compound, then add them together to get the overall MW for the fluid? :-\

You have composition as mol %? Or weight %?

Offline gunnersaurus

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Re: mol%
« Reply #10 on: July 01, 2013, 08:44:04 AM »
mol%

Offline curiouscat

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Re: mol%
« Reply #11 on: July 01, 2013, 10:16:52 AM »
Then your approach sounds right. Now MW not AW.

You don't even have to get the MW. Divide H2S's mass share by the sum of products of MW and mole. frac.

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