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Topic: Average Rate  (Read 1728 times)

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Offline adinboy

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Average Rate
« on: July 09, 2013, 08:18:50 PM »
So here's the question:


What I'm struggling to understand is why the answer is not being divided by 2. See, if we are writing the rate of reaction for a reactant then our equation is going to be of the general form -[reactant]/( Coefficient * Δt ). So in this case, since we are talking about NOBr, shouldn't the equation be -[NOBr]/2Δt?

So for part a, we would have -(.0088-.0249)/(2*(20-8)) = 6.71e-4 mol/(L·s), right?

Offline salpar

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Re: Average Rate
« Reply #1 on: July 14, 2013, 12:46:16 AM »
You need to graph it out, use least squares line to estimate for unknowns.




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