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Topic: Help titration  (Read 9062 times)

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Offline pinkturtle

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Help titration
« on: February 18, 2006, 11:20:01 AM »
ok i have carried out a few titrations but i have never fully understood the process of making a standard solution
my titration iam going to carry out is a strong acid weak base so iam using methly orange indicator

all i know is
i have a acidic solution of ABOUT 2.0M
i have the ratio of 1mole Na2CO3:2moles HCl
i have figured the mases out to be 106g of Na2CO3 and 73g of HCl
obviousley i am filling the burette with the acid of the unknown concentration
how do i figure out how much Na2CO3 (s) i need to make up my standard solution ?
 ???

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Re:Help titration
« Reply #1 on: February 18, 2006, 11:39:40 AM »
Assume your HCl solution is 2M. For best precision you will need to use about 80% volume of your burette. Calculate how much Na2CO3 will react with this amount of acid. Weight precisely approximately that amount.

Are you sure you are asked to use 2M solution as a titrant? Sounds like very concentrated to me.
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Offline pinkturtle

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Re:Help titration
« Reply #2 on: February 18, 2006, 12:12:53 PM »
well what it is is that iam trying to find out the mass of HCl acid contained in a 500ml bottle of limescale remover

does it sound ok now ?

Offline pinkturtle

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Re:Help titration
« Reply #3 on: February 18, 2006, 12:24:13 PM »
my mistake its 0.2 M
sorry!!

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Re:Help titration
« Reply #4 on: February 18, 2006, 12:27:24 PM »
i have figured the mases out to be 106g of Na2CO3 and 73g of HCl
obviousley i am filling the burette with the acid of the unknown concentration
how do i figure out how much Na2CO3 (s) i need to make up my standard solution ?
 ???


I'm a bit confused, too. Would you be so kind as to post only the information you were given?
« Last Edit: February 18, 2006, 12:28:27 PM by Albert »

Offline pinkturtle

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Re:Help titration
« Reply #5 on: February 18, 2006, 12:34:43 PM »
ok
i have to find the mass of HCl contained in a 500ml bottle of limescale remover, the conc is thought to be about 2.0M
iam given a solution containing the limescale remover that has been diluted by 10x
iam provided with solid anhydrous sodium carbonate
thats all the info i have been given
sorry for the confusion

but i tried to workout the reacting mases (which i think are correct) and i worked out a 2:1 ratio  

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Re:Help titration
« Reply #6 on: February 18, 2006, 12:44:21 PM »
To sum up, in your burette, there is an about 0.1N solution:

2 mmoles : 1000 mL = x mmol : 500 mL

If you have a 25mL burette, you should use 20 mL. In a nutshell, you have to titrate 2 meq (equivalents, you know what they are, don't you?).

Na2CO3 + 2HCl -> 2 NaCl + H2O + CO2

2 meq are more or less 0.1060 g of Na2CO3.
« Last Edit: February 18, 2006, 12:56:40 PM by Albert »

Offline pinkturtle

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Re:Help titration
« Reply #7 on: February 18, 2006, 04:39:03 PM »
im sorry iam only at A/S level , im finding chemistry tricky but enjoy a challenge
if u would be so kind to explain what a meq is and how u came about getting them or i u can suggest a more simple explaination to my problem
your help is greatfully recieved thanz!!! ;)

Offline Albert

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Re:Help titration
« Reply #8 on: February 18, 2006, 04:56:01 PM »
http://en.wikipedia.org/wiki/Equivalent_weight

To quote, again, Wikipedia: "The normality of a solution is equal to the number of gram equivalent weights of a solute per liter of solution. The only concentration unit that is reaction dependent."

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Re:Help titration
« Reply #9 on: February 18, 2006, 06:05:51 PM »
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