(...) Graham's Law measures the average rate of gas molecules of one type in comparison to the average rate of gas molecules molecules of another type. In other words, a single molecule of a heavier MW (let's say CO2) could have a higher rate than that of a lighter weight MW (let's say O2). However, the average rate of all of the O2 molecules within the gas, will have a higher rate in comparison to the CO2 molecules.
Is my thinking correct?
how can a single molecule probably have a "rate"? it could have an individually higher velocity, yes - but once it's gone it's gone.
asides from that, I think I know what you wanted to express, and that
seems ok to me
However, If only a small amount of molecules were allowed to effuse into container B, how can we assume that the molecules that did effuse followed Graham's law, which is based off of the average diffusion of ALL (all of one type, as in O2) molecules within a gas.
it isn't necessary that all
molecules effuse: we just need enough
molecules to effuse to fulfill the Maxwell-Bolzmann distribution in a meaningful way.
For example : if I had 1 mole of a gas at a pressure of 1 bar in A (and "zero" in B), and would allow 10-15
mole of this gas to escape to B, I'd still have such a pressure difference of [itex] \approx [/itex] 1 bar A-B , that in any meaningful way I could claim the difference to be 1 bar still.
mole still is in the ballpark of 6*108
particles, and that by far still satisfies my personal understanding of "good enough for a Maxwell-Bolzmann-distribution in B" (if B wasn't too large)
... and all this, on the other hand, is good enough to fulfill Graham's law if we had two different gases to play with
Also, at high pressure, don't gases stop behaving ideally?
eventually they'll do, yes
... but to me, that seems to be beside the point here : we're not to think about such high pressures in context with the problem posed to you, if my reading was correct.
Technically, can Graham's Law be applied to this question?
yes it can, for the reasons I hope to have shown above