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Topic: Molecular Orbital Problem!!!!!  (Read 2253 times)

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Offline kelvinLTR

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Molecular Orbital Problem!!!!!
« on: August 11, 2013, 12:25:04 AM »
Arrange the three species N2,  N2+ and N2- in the order of

1) Increasing bond length
2) Increasing bond energy

I've calculated the Bond Orders of the three species to be 3,2.5,2.5 respectively. And I think N2 has the lowest bond length and Highest Bond energy. But how can I compare the other two species?

Thanks in advance  :)
« Last Edit: August 11, 2013, 04:10:48 AM by kelvinLTR »

Offline sjb

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Re: Molecular Orbital Problem!!! *delete me*!!
« Reply #1 on: August 11, 2013, 03:09:49 AM »
Arrange the three species N2,  N2+ and N2- in the order of

1) Increasing bond length
2) Increasing bond energy

I've calculated the Bond Orders of the three species to be 3,2.5,2.5 respectively. And I think N2 has the lowest bond length and Highest Bond energy. But how can I compare the other two species?

Thanks in advance  :)

Compare ethane, ethene and ethylene...?

Offline kelvinLTR

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Re: Molecular Orbital Problem!!! *delete me*!!
« Reply #2 on: August 11, 2013, 04:12:13 AM »
Arrange the three species N2,  N2+ and N2- in the order of

1) Increasing bond length
2) Increasing bond energy

I've calculated the Bond Orders of the three species to be 3,2.5,2.5 respectively. And I think N2 has the lowest bond length and Highest Bond energy. But how can I compare the other two species?

Thanks in advance  :)

Compare ethane, ethene and ethylene...?

sorry, I didn't get the hint :( can you please explain

Offline EDTA

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Re: Molecular Orbital Problem!!!!!
« Reply #3 on: August 13, 2013, 04:10:54 PM »
Well, if bond order is the same, then the 2 species should have approximately the same bond length and energy.

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