April 28, 2024, 12:54:10 AM
Forum Rules: Read This Before Posting


Topic: A problem in hybridization  (Read 2915 times)

0 Members and 1 Guest are viewing this topic.

Offline Ammar Qasim

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
A problem in hybridization
« on: August 17, 2013, 07:06:17 AM »


How could I know the hybridization type in such a question

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2180
  • Mole Snacks: +167/-48
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: A problem in hybridization
« Reply #1 on: August 17, 2013, 09:54:19 AM »
Get the structure of each molecule by the rules of VESPR. Compare then the pairs.

http://en.wikipedia.org/wiki/VSEPR_theory

Offline Ammar Qasim

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Re: A problem in hybridization
« Reply #2 on: August 17, 2013, 01:30:13 PM »
I found that the structure of BH3 is similar to ClF3's. is (C) the right answer?

Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3652
  • Mole Snacks: +222/-42
  • Gender: Male
Re: A problem in hybridization
« Reply #3 on: August 17, 2013, 02:30:37 PM »
I found that the structure of BH3 is similar to ClF3's. is (C) the right answer?

What makes you sure there is just one right answer. I'm not sure that boron trifluoride and chlorine trifluoride have the same geometry - what is your VSEPR analysis?

Offline Ammar Qasim

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Re: A problem in hybridization
« Reply #4 on: August 17, 2013, 03:28:01 PM »
What makes you sure there is just one right answer. I'm not sure that boron trifluoride and chlorine trifluoride have the same geometry - what is your VSEPR analysis?
There must be only one right choice in this question. I tried that

So I think letter C would be the right answer

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2180
  • Mole Snacks: +167/-48
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: A problem in hybridization
« Reply #5 on: August 17, 2013, 03:58:41 PM »
No, you have to consider the unpair electrons.


Offline sario

  • New Member
  • **
  • Posts: 3
  • Mole Snacks: +0/-0
Re: A problem in hybridization
« Reply #6 on: August 18, 2013, 04:34:57 PM »
I think that the right answer is B because the Nitrogen atom is sp3. In NH3 one sp3 orbital is occupied by two electrons, on the other hand in the ammonium ion all the four sp3 orbitals make a covalent bond with Hydrogen atoms.

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2180
  • Mole Snacks: +167/-48
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: A problem in hybridization
« Reply #7 on: August 19, 2013, 12:42:49 AM »
Correct, but the TES should answer it.

Sponsored Links