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Topic: Gibbs Free Energy Problem  (Read 8075 times)

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Offline parachute

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Gibbs Free Energy Problem
« on: September 24, 2013, 09:38:54 AM »
Use the free energies of formation from standard thermodynamics tables to calculate the standard free-energy change for the decomposition of hydrogen peroxide in the following reaction:

2H2O2 (g:rarrow: 2H2O (g) + O2 (g)

Calculations:

ΔS°rxn = [2mol (S°f H2O (g)] + [1mol (S°f O2 (g)] = [2mol (S°f H2O2 (g)]

ΔS°rxn = [2mol (S°f (-228.6kJ/mol)] + [1mol (S°f (163.2kJ/mol)] = [2mol (S°f (-105.6kJ/mol)]

ΔS°rxn = (-457.2) + (163.2) - (-211.2)

ΔS°rxn = -82.8 kJ

I would just like reassurance to my calculations so I know I'm doing all the problems the right way.

Offline magician4

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Re: Gibbs Free Energy Problem
« Reply #1 on: September 24, 2013, 10:12:58 AM »
I would strongly advise you to look up what the definition of "free energy " (aka "Gibbs free energy")  is

furthermore , pls. be informed that

- free energy is labelled G ( i.e. the change of free energy is ΔG )
- the dimension of G  (usually) is kJ/mole (or any other equivalent relation of energy, amount of substance)
- S ( or, for that matter ΔS) stands for (change of) entropy
- the dimension of S (or ΔS ) would be (usually) J/mol*K

regards

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Offline Dan

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Re: Gibbs Free Energy Problem
« Reply #2 on: September 24, 2013, 10:20:07 AM »
In addition, your value for Δ?[O2(g)] is incorrect. Where is your data from?
 
ΔH[O2(g)] = ΔS[O2(g)] = ΔG[O2(g)] = 0
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Offline Big-Daddy

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Re: Gibbs Free Energy Problem
« Reply #3 on: September 24, 2013, 04:16:15 PM »
In addition, your value for Δ?[O2(g)] is incorrect. Where is your data from?
 
ΔH[O2(g)] = ΔS[O2(g)] = ΔG[O2(g)] = 0

Are you sure this true for S°, ΔSf°, and ΔGf°?

Offline Dan

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Re: Gibbs Free Energy Problem
« Reply #4 on: September 25, 2013, 02:46:15 AM »
In addition, your value for Δ?[O2(g)] is incorrect. Where is your data from?
 
ΔH[O2(g)] = ΔS[O2(g)] = ΔG[O2(g)] = 0

Are you sure this true for S°, ΔSf°, and ΔGf°?

In a rush I forgot to specify these are standard changes of formation:

ΔfH°[O2(g)] = ΔfS°[O2(g)] = ΔfG°[O2(g)] = 0

Remember that all of these changes refer to formation from the constituent elements in their standard state. The standard state of elemental oxygen is O2(g), so there is no change in any of these processes.

I never suggested that S° = 0


http://en.wikipedia.org/wiki/Standard_enthalpy_change_of_formation_(data_table)
http://en.wikipedia.org/wiki/List_of_standard_Gibbs_free_energies_of_formation
My research: Google Scholar and Researchgate

Offline Big-Daddy

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Re: Gibbs Free Energy Problem
« Reply #5 on: September 25, 2013, 07:48:50 PM »
In a rush I forgot to specify these are standard changes of formation:

ΔfH°[O2(g)] = ΔfS°[O2(g)] = ΔfG°[O2(g)] = 0

Ah of course. Formation is always formation from elements, and O2 is itself the elemental form so all thermodynamic values of formation for O2 will be 0.

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