[amanda8991]

What would happen if chlorine water was added to an aqueous solution of sodium chloride?

What would happen if chlorine water was added to an aqueous solution of sodium bromide?

[mike]

You should attempt to answer these yourself first

http://www.chemicalforums.com/index.php?board=4;action=display;threadid=7074

[amanda8991]

Are you saying that Cl and Br would be reduced?

[mike]

Well I am guessing that perhaps the Br^- would be oxidized to Br₂ while the Cl₂ would be reduced to Cl^-

I don't know what would happen if you bubble Cl2 through NaCl, I don't see why anything would happen.

What do you think?

[amanda8991]

Is the chlorine water just an aqueous solution of cl?

Cl-(aq) +NaCl (aq) ---> NaCl2


That cant be right I guess because it doesn't seem like either of them are being oxidized ore reduced.

[mike]

I think you must assume that the chlorine water is a solution of Cl₂.

[amanda8991]

So the equation would be...

Cl2 (aq) + NaCl(aq) ---->

How would you write the other side of that? Would it be NaCl and then you just balance it?

[AWK]

Chlorine water is partailly some hydrate of water and a mixture of HCl and HOCl
Cl2 + H2O = HCl + HOCl

in the case of NaBr
2NaBr + Cl2 = 2NaCl + Br2
Br2 can react with exces of Cle
Br2 + Cl2 = 2 BrCl and colour of bromine water disappears.

[amanda8991]

Chlorine water is partailly some hydrate of water and a mixture of HCl and HOCl
Cl2 + H2O = HCl + HOCl

in the case of NaBr
2NaBr + Cl2 = 2NaCl + Br2
Br2 can react with exces of Cle
Br2 + Cl2 = 2 BrCl and colour of bromine water disappears.

If you were to add that chlorine water to NaCl would the equation be written like this:

HCl+ HClO +NaCl----> ?

Is it possible to have three reactants on one side?

[AWK]

Reactants should react - in this case no reaction is observed

[peacefulltortoise]

Please describe deeply what happen when pour Clorine solution to NaBr and NaI solutions. Is there any thing different in two cases?

[Borek]

Please describe deeply what happen when pour Clorine solution to NaBr and NaI solutions. Is there any thing different in two cases?

Yes. Chlorine doesn't react with chlorides, but reacts with bromides and iodides, replacing them in the salts.

[Borek]

Is it possible to have three reactants on one side?

As much as you wish

this is so called Blakley equation:

88H₂ + 15Ca(CN)₂ + 6NaAlF₄ + 10FeSO₄ + 3MgSiO₃ + 6KI + 2H₃PO₄ + 6PbCrO₄ + 12BrCl + 3CF₂Cl₂ + 20SO₂ -> 6PbBr₂ + 6CrCl₃ + 3MgCO₃ + 6KAl(OH)₄ + 10Fe(SCN)₃ + 2PI₃ + 3Na₂SiO₃ + 15CaF₂ + 79H₂O

and this one was published by Stout:

10(Cr(N₂H₄CO)₆)₄(Cr(CN)₆)₃ + 1176KMnO₄ + 1399H₂SO₄ -> 35K₂Cr₂O₇ + 1176MnSO₄ + 420CO₂ + 660KNO₃ + 223K₂SO₄ + 1879H₂O

EBAS rulez

[peacefulltortoise]

Yes. Chlorine doesn't react with chlorides, but reacts with bromides and iodides, replacing them in the salts.

I see, but what can we see differences beetween Cl2 + NaBr --> NaCl + Br2 and Cl2 + NaI --> NaCl + I2 ? I guess the solutions in two case are the same color.

[Borek]

I see, but what can we see differences beetween Cl2 + NaBr --> NaCl + Br2 and Cl2 + NaI --> NaCl + I2 ? I guess the solutions in two case are the same color.

What is color of free bromine, what is color of free iodine?