One step at a time please :p Given that the cathode and anode reactions are given as they are, the reaction which one drives forward by applying energy is CoO2
+ 6C. First, how does this reaction go forward when neither CoO2
appears to be initially present?
So the cathode is gaining charge because, apparently, LiCoO2
is being formed there, while graphite is formed at the anode (which is losing Li from LiC6 and thus becoming discharged). In light of this, what do those initial conditions mean, and how do they work - after all the electrolysis reaction should be impossible if neither of the reactants are present?