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Topic: Born-Haber Cycle  (Read 7331 times)

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Turkishee

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Born-Haber Cycle
« on: March 02, 2006, 03:16:36 PM »
I have a question which I must do yet I cant manage to solve it, any help will be appreciated.

It would be theoretically possible for calcium to forma  fluoride CaF containing Ca+ ions and the F- ions in equal numbers. Assuming that the lattice enthalpy of the hypothetical compound is similar to that of NaF (+891 kJ mol ^ -1 ), use a Born-Haber cycle to calculate its enthalpy of formation using the data below

Data:

Enthalpy of atomisation of Ca : +193 kJ Mol ^ -1
F-F Bond enthalpy : +158
First Ionisation Energy of Ca: + 590
Electron Affinity of Flourine: -348

The enthalpy of formation of CaF2 is -1214 kJ mol ^ -1. Use this to explain why it is not possible to produce CaF even if two moles of calcium are reacted with one mole of flourine gas.
« Last Edit: March 03, 2006, 06:56:55 PM by geodome »

Offline Donaldson Tan

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Re:Born-Haber Cycle
« Reply #1 on: March 03, 2006, 07:05:46 PM »
construct the bon-haber cycle for CaF to find the heat of formation for CaF.

then compare the heat formation for CaF to that of CaF2
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