PbSO4 is mixed with KI to produce PbI2 precipitate.
Solid PbI2 is mixed with Na2CO3. The products should be PbCO3 and NaI (as free floating I believe).
The question is, in what order will precipitate form with Pb?
With ksp values I can tell which is more insoluble and most likely to form a precipitate. But the problem doesn't give ksp values. Ihe answer to the question is CO3-, I-, SO4-2.
All the poly atomic ions are insoluble with lead, but how can one tell the order of solubility?
I believe it's because when mixed and broken into separate ions, precipitate will form from the most insoluble, hence the order...but sounds a bit too simple or over simplified. Thoughts?