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Topic: 1/λ= R(1/n_1 - 1/n_2) or 1/λ= (RH/hc)(1/n_1 - 1/n_2)  (Read 3702 times)

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Offline WK95

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1/λ= R(1/n_1 - 1/n_2) or 1/λ= (RH/hc)(1/n_1 - 1/n_2)
« on: October 30, 2013, 10:28:37 PM »
1/λ= R(1/n_1 - 1/n_2)
---vs---
1/λ= (RH/hc)(1/n_1 - 1/n_2)

What is the difference in usage? In my problem sets, I keep getting questions usin these equations and sometimes one is used while other times, another is used.

Offline Vidya

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Re: 1/λ= R(1/n_1 - 1/n_2) or 1/λ= (RH/hc)(1/n_1 - 1/n_2)
« Reply #1 on: October 30, 2013, 10:59:53 PM »
you will get the same answer by using any of the equation
In one case the constant is R which is equal to RH/hc
Basic equation is E= RH(1/n^)2-  1/n^2_2)
and E = hc/λ If you plug in the values
then 1/λ= RH/hc(1/n^2_1-n^2_2)
so basically they are the same equation and R = RH/hc
RH is the Rydberg constant with units of J
and R is the Rydberg constant with units of m^-1

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