The problem statement, all variables and given/known data
What volume (L) of 0.358 M potassium hydroxide solution would just neutralize 99.9 ml of 0.156 M H2SO4 solution?
The attempt at a solution
2KOH + H2SO4 --> 2H2O + K2SO4
2KOh
[tex]\frac{0.358 mol}{1000mL}*V_{KOH}[/tex]
[tex]\frac{0.156 mol}{1000mL}*0.099 mL = 1.5444*10^{-5}[/tex]
[tex]\frac{0.358 mol}{1000mL}*V_{KOH} = 1.5444*10^{-5}[/tex]
[tex]V_{KOH}=0.0431 L[/tex]
The answer is actually 0.0862, double my answer. Why is this? I know it has something to do with the ratio of KOH to H2SO4 being 2:1 but where do I factor in this ratio in my work?
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Topic: Volume of KOH needed to neutralize a given volume H2SO4? (Read 6452 times)