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Topic: Stereoisomers  (Read 1770 times)

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Offline Bassel

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Stereoisomers
« on: November 15, 2013, 04:32:03 PM »
what is the relation between the two compounds in the picture attached ?

Offline Borek

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Re: Stereoisomers
« Reply #1 on: November 15, 2013, 04:46:58 PM »
You have to show your attempts at solving the question to receive help. This is a forum policy.
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Offline Bassel

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Re: Stereoisomers
« Reply #2 on: November 15, 2013, 04:52:35 PM »
I don't know how to solve it. I've tried to draw a mirror image of the first and i got the second one but it was stated that they are identical and now I'm lost. thats why i didn't post any attempt to solve it.

Offline danteOne

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Re: Stereoisomers
« Reply #3 on: November 15, 2013, 06:10:55 PM »
If you have a model kit try building each one. I think you will then see why both are a the same compound.

Offline aram2189

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Re: Stereoisomers
« Reply #4 on: November 15, 2013, 07:20:20 PM »
Try rotating the compound on the right 180 degrees such that C1 is on the left hand side (C1 being the carbon of the methyl group closest to the hydroxyl group). Once you do I'm sure you will the two compounds are the same. In cases like these, it helps to draw two molecules such that the substituents sort of match up in the spacial configuration drawn if that makes sense.

Offline antimatter101

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Re: Stereoisomers
« Reply #5 on: November 20, 2013, 11:48:58 PM »
R-S stereochemistry.

R for rectus, S for sinister

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