May 01, 2024, 05:13:59 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Oxidation of Zn(s) in excess 1M NaHSO4 produces SO2 gas?  (Read 1779 times)

0 Members and 1 Guest are viewing this topic.

Offline lpf1991

  • New Member
  • **
  • Posts: 6
  • Mole Snacks: +0/-0
Oxidation of Zn(s) in excess 1M NaHSO4 produces SO2 gas?
« on: November 24, 2013, 11:19:17 PM »
Zn(s) is oxidized in excess 1M NaHSO4, gives SO2 as reducer.  For this reaction, the ration of mols of oxidizer to reducer is:

Answer is 1:1

Could someone just help me understand what occurs here.  I'm guessing the NaHSO4 will dissociate, but not really sure how to proceed.

Thanks for any help.
Logged

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2181
  • Mole Snacks: +168/-48
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: Oxidation of Zn(s) in excess 1M NaHSO4 produces SO2 gas?
« Reply #1 on: November 25, 2013, 02:46:55 AM »
You have two pairs Zn/Zn2+ and SO42-/So2

develop for each the reaction equation. If Oxygen is present use H+ and H2O to balnce it.
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links