[Borek]

Sorry, I wrote oxygen, but I meant carbon. The oxygen half reaction:

Reduction Half-Reaction: O₂ + 4e^- 2O^-2

is OK, but there is a problem here:

Oxidation Half-Reaction: C^-4 + 8e^- C⁺⁴

[dudebuddyguy]

Sorry, I wrote oxygen, but I meant carbon. The oxygen half reaction:

Reduction Half-Reaction: O₂ + 4e^- 2O^-2

is OK, but there is a problem here:

Oxidation Half-Reaction: C^-4 + 8e^- C⁺⁴

Hmm....I'm thinking it's gotta be the 8e^-.

Would the answer be -8e^-?

[Borek]

Why don't you try to put them on the right side?

At the moment on the left you have -4 (from carbon) and -8 (from electrons) - that is -12 in total. And only +4 on the right.

[dudebuddyguy]

Why don't you try to put them on the right side?

At the moment on the left you have -4 (from carbon) and -8 (from electrons) - that is -12 in total. And only +4 on the right.

I see it now!

C(-4) + C(+4) 8e^-

Math is fun

EDIT: WAIT! I'm completely wrong! I know what to do

C^-4 + 8e^- 3C⁺⁴
-4 + 8 = 12 3C x +4 = 12

EDIT 2: So I used this wonderful automatic balancing tool, and apparently C{-4} + 8e = C{+4} was incorrect. The correct balancing was C{-4} = 8e^- + C{+4}. No additional charges needed!

Click here to visit the balancing calculator at WebQC.org (it'll automatically pull the balanced equation up.)

[Borek]

The correct balancing was C{-4} = 8e^- + C{+4}. No additional charges needed!

I told you to put them on the right, didn't I?

[dudebuddyguy]

The correct balancing was C{-4} = 8e^- + C{+4}. No additional charges needed!

I told you to put them on the right, didn't I?

I mis-read what you said lmao.

I'm onto the next equation which has Chlorine ions (hooray).

Mn + Cl2 -> MnCl7
Oxidation numbers: Mn{+2} + Cl{-2} = Mn{+2} + Cl{-7}

Reduction: Cl{-2} + -5e = Cl{-7}

The Manganese however hasn't lost or gained anything. It's sat at a solid +2. So the coursework noted that some questions may not have an Oxidation reaction, and this is obviously an example of this.

Grade me and let me know how I did (out of 10)

[Borek]

Mn + Cl2 -> MnCl7
Oxidation numbers: Mn{+2} + Cl{-2} = Mn{+2} + Cl{-7}

I am afraid none of these is OK.

You have elemental forms on the left. http://www.chembuddy.com/?left=balancing-stoichiometry&right=oxidation-numbers-method - rule number 2.

Then, on the right - start with the rule number 5, followed by the rule number 6.

[dudebuddyguy]

Mn + Cl2 -> MnCl7
Oxidation numbers: Mn{+2} + Cl{-2} = Mn{+2} + Cl{-7}

I am afraid none of these is OK.

You have elemental forms on the left. http://www.chembuddy.com/?left=balancing-stoichiometry&right=oxidation-numbers-method - rule number 2.

Then, on the right - start with the rule number 5, followed by the rule number 6.

Update: Ok, so I've done everything properly (I think), so I'm done with that.

Now I just need to figure out WHICH REACTIONS ARE SPONTANEOUS AND NON-SPONTANEOUS without using that damned Gibbs Free Energy equation BECAUSE MY MATH SKILLS SUCK.