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Topic: Vapor Pressure  (Read 3320 times)

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Offline aniel

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Vapor Pressure
« on: December 04, 2013, 07:52:09 AM »
Calculate the vapor pressure at 30 degrees Celsius of a 3.0 molal solution of ethylene glycol assuming that the vapor pressure of a solution containing a non-volatile solute is proportional to the mole fraction of the solvent.

Offline sjb

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Re: Vapor Pressure
« Reply #1 on: December 04, 2013, 08:08:47 AM »
Calculate the vapor pressure at 30 degrees Celsius of a 3.0 molal solution of ethylene glycol assuming that the vapor pressure of a solution containing a non-volatile solute is proportional to the mole fraction of the solvent.

Have you checked the forum rules? Any equations you know that may help?

Offline aniel

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Re: Vapor Pressure
« Reply #2 on: December 04, 2013, 08:23:51 AM »
for m or molality , the formula is m=wt. of solute/ MW(kg.solvent)
*MW-> molecular weight

Pa= Xa (Pa°)

where Pa = vapor pressure of the soln
Xa =mole fraction of the solvent
Pa°= vapor pressure of the solvent



Offline aniel

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Re: Vapor Pressure
« Reply #3 on: December 04, 2013, 08:25:54 AM »
the solvent is assumed as water

Offline Borek

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Re: Vapor Pressure
« Reply #4 on: December 04, 2013, 08:32:05 AM »
You have to convert molality to the molar fraction.

Assume solution containing 1 kg of water.

How many moles of glycol?

How many moles of water?

What is molar fraction of water?
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Offline aniel

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Re: Vapor Pressure
« Reply #5 on: December 04, 2013, 08:45:32 AM »
is this correct?

there are 0.3 moles of glycol; 55.5556 moles of water

and the mole fraction of water is 0.9946



Offline aniel

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Re: Vapor Pressure
« Reply #6 on: December 04, 2013, 08:46:39 AM »
do we always assume that the water(solvent) is 1kg?

Offline Borek

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Re: Vapor Pressure
« Reply #7 on: December 04, 2013, 11:41:49 AM »
there are 0.3 moles of glycol

Why 0.3?

do we always assume that the water(solvent) is 1kg?

Not necessarily, but that's the most convenient thing to do, as then it is very easy to calculate number of moles of the solute.
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