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Topic: Gibbs free energy equation confusion???  (Read 2200 times)

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Offline webassignbuddy

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Gibbs free energy equation confusion???
« on: December 09, 2013, 08:30:13 AM »
Consider the reaction C2H6(g)  ::equil::  C2H4(g) + H2(g). For this process, ΔH° = +137.0 kJ/mol and  ΔS° = +120.6 J/mol·K. Based on these data (note carefully) and assuming ΔH° and ΔS° are temperature independent, answer the following questions.

a. Does this reaction "favor" reactants or products at 25ºC? reactants (CORRECT)
b. At 25ºC is the reaction driven (dominated) by the entropy or enthalpy? enthalpy (CORRECT) because ΔG = ΔH° - TΔS° = 137000 - (25)(120.6) = +133985, so enthalpy dominates.
c. Would an increase in temperature favor the reactants or products? reactants (CORRECT)
d. At what temperature would the equilibrium constant (K) equal unity (1.0)?

I don't understand how to solve for d!

Do I use the equation ln K = (ΔS°/R) - (ΔH°/RT)?

Offline Borek

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Re: Gibbs free energy equation confusion???
« Reply #1 on: December 09, 2013, 08:38:30 AM »
Nothing analytical about the problem, moving to Physical Chemistry.
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Offline webassignbuddy

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Re: Gibbs free energy equation confusion???
« Reply #2 on: December 09, 2013, 10:49:47 AM »
Anybody willing to help me in the right direction??

Offline Big-Daddy

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Re: Gibbs free energy equation confusion???
« Reply #3 on: December 09, 2013, 06:14:57 PM »
yes, that equation is correct, and it comes from the two equations ΔG° = ΔH° - TΔS° and ΔG=ΔG°+RTln(Q) of which a special case is that when Q=K (i.e. at equilibrium) ΔG=0.

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